这篇教程Python 如何解决稀疏矩阵运算写得很实用,希望能帮到您。 用Python求解微分线性方程因为之前用matlab也编写过,所以前不久试着用python写,感觉之间互通点也蛮多的,易理解。 题目:稀疏线性方程组的求解方法简单的方程如: AX=b 其中 
python有很多功能库,这些库对于编程很有帮助,可以在pycharm的Project Interpreter导入库,例如numpy、os、scipy等比较基础的库, 下面是用来求解的代码:import numpy as npfrom scipy import linalgimport os#输入矩阵维数print("你好,这里是计算稀疏矩阵线性方程组的地方,非诚勿扰!")dism_num = input("你的A矩阵维数是:")dism_num = int(dism_num)print("接下来请你依次输入矩阵的行向量(注意只能输入英文逗号,):")A =[]#X =[]for i in range(1,dism_num+1): a=input("第"+str(i)+"行向量是:") alist = a.split(",") alist = [int(alist[j]) for j in range(len(alist))] A.append(alist)print("你所输入的矩阵行向量是:")print(A)#记录输入的X矩阵#输入向量bprint("输入b向量")b = input("b向量是:")b_list = b.split(",")b_list = [int(b_list[j]) for j in range(len(b_list))]print("你输入的b向量是:")print(b_list)#记录b向量#询问是否计算单个答案(单元素)ask = input("是否只需求解单个值:(是或否)")while(True): if ask == '是': ask_a = 'T' ask_num = input("请继续输入你所需要的答案序号:") ask_num = int(ask_num) if ask_num<=dism_num and ask_num>0: print("OK,马上帮你计算") break else: print("输入的值超出矩阵维数,请重新输入:") if ask == '否': ask_a = 'F' break#询问完成,只有当用户输入正确的序号才可以进行计算,否则重新询问#开始计算x向量了A = np.array(A)b = np.array(b_list)x = linalg.solve(A,b)print("计算的结果的:")if ask_a == 'F': print(x)if ask_a =='T': print(x[ask_num-1])#计算完x向量了os.system("pause")#用于py文件结束玩暂停显示结果 其基本流程如图: 
运行结果如下: 
补充:python 多线程稀疏矩阵乘法 
看代码吧~import threading, timeimport numpy as npres = []class MyThread(threading.Thread): def __init__(self,i,j,m1,m2): threading.Thread.__init__(self) self.x, self.y = i,j self.m1, self.m2 = m1, m2 def run(self): global res, lock if lock.acquire(): m1 = self.m1[self.m1[:,0]==self.x] m2 = self.m2[self.m2[:,1]==self.y] value = 0. for item1 in m1: for item2 in m2: if item1[1] == item2[0]: value += item1[2]*item2[2] res.append([self.x,self.y,value]) lock.release()if "__main__" == __name__: m1 = [[2,2],[0,0,1],[0,1,2],[1,0,3],[1,1,4]] m2 = [[2,3],[0,0,2],[0,2,1],[1,2,3],[1,1,4]] s1, s2 = m1[0], m2[0] assert s1[1]==s2[0], 'mismatch' m1_value = np.array(m1[1:]) m2_value = np.array(m2[1:]) rows, cols = s1[0], s2[1] res.append([rows, cols]) ThreadList = [] lock = threading.Lock() for i in range(rows): for j in range(cols): t = MyThread(i,j,m1_value,m2_value) ThreadList.append(t) for t in ThreadList: t.start() for t in ThreadList: t.join() print (res) 以上为个人经验,希望能给大家一个参考,也希望大家多多支持51zixue.net。 Python selenium模拟网页点击爬虫交管12123违章数据 python 实现体质指数BMI计算 |