这篇教程django将图片保存到mysql数据库并展示在前端页面的实现写得很实用,希望能帮到您。 小编使用python中的django框架来完成! 1,首先用pycharm创建django项目并配置相关环境这里小编默认项目都会创建 settings.py中要修改的两处配置 DATABASES = { 'default': { # 'ENGINE': 'django.db.backends.sqlite3', # 'NAME': os.path.join(BASE_DIR, 'db.sqlite3'), 'ENGINE': 'django.db.backends.mysql', 'NAME': 'photos', 'HOST': '127.0.0.1', 'PORT': '3306', 'USER': 'root', 'PASSWORD': '201314', }}STATIC_URL = '/static/'STATICFILES_DIRS = [ os.path.join(BASE_DIR, 'static')] 2,创建表①先按键盘上win+s键,然后输入cmd,中文输入法两下回车,英文输入法一下回车,即可进入dos窗口。 ②输入 mysql -uroot -p密码 回车进入mysql数据库,再输入 create database 库名; 一个小回车,创建数据库🆗

③在app下的models.py中创建表结构 models.py from django.db import models# Create your models here.class Images(models.Model): img = models.ImageField(upload_to='static/pictures/') # upload_to='static/pictures/'是指定图片存储的文件夹名称,上传文件之后会自动创建 img_name = models.CharField(max_length=32) create_time = models.DateTimeField(auto_now_add=True) ④迁移数据库 分别按顺序在pycharm下面的Terminal中执行下面两条语句 python manage.py makemigrationspython manage.py migrate 
3,上传图片功能urls.py from django.conf.urls import urlfrom django.contrib import adminfrom app01 import viewsurlpatterns = [ url(r'^admin/$', admin.site.urls), url(r'^upload/$', views.upload, name='upload'),] views.py from django.shortcuts import render, redirectfrom app01 import models# Create your views here.def upload(request): error = '' if request.method == 'POST': img = request.FILES.get('img') pic_name = img.name if pic_name.split('.')[-1] == 'mp4': error = '暂不支持上传此格式图片!!!' else: models.Images.objects.create(img_name=pic_name, img=img) return redirect('show') return render(request, 'upload.html', locals()) 前端上传页面upload.html <!DOCTYPE html><html lang="en"><head> <meta charset="UTF-8"> <title>上传照片</title></head><body><div style="height: 160px"> <form action="" method="post" enctype="multipart/form-data"> {% csrf_token %} <h1>上传图片页面</h1> <table cellpadding="5px"> <tr> <td>上传图片</td> <td><input type="file" name="img"></td> </tr> <tr> <td> <button>上传</button> </td> <td><strong style="color: red">{{ error }}</strong></td> </tr> </table> </form></div><div style="text-align: center;color: #2b542c;font-size: 20px;"> <a href=" {% url 'show' %} " rel="external nofollow" >返回</a></div></body></html> 
4,展示图片功能urls.py """from django.conf.urls import urlfrom django.contrib import adminfrom app01 import viewsurlpatterns = [ url(r'^admin/$', admin.site.urls), url(r'^upload/$', views.upload, name='upload'), url(r'^show/$', views.show, name='show'),] views.py from django.shortcuts import render, redirectfrom app01 import models# Create your views here.def upload(request): error = '' if request.method == 'POST': img = request.FILES.get('img') pic_name = img.name if pic_name.split('.')[-1] == 'mp4': error = '暂不支持上传此格式图片!!!' else: models.Images.objects.create(img_name=pic_name, img=img) return redirect('show') return render(request, 'upload.html', locals())def show(request): all_images = models.Images.objects.all() # for i in all_images: # print(i.img) return render(request, 'show.html', locals()) 前端展示show.html <!DOCTYPE html><html lang="en"><head> <meta charset="UTF-8"> <title>展示照片</title></head><body>{% for image in all_images %} <img src="/{{ image.img }}" style="width: 240px;height: 240px;">{% endfor %}<br/><p style="text-align: center;color: #2b542c;font-size: 20px;"> <a href="{% url 'upload' %}" rel="external nofollow" rel="external nofollow" >返回</a></p></body></html> 
5,删除图片功能urls.py from django.conf.urls import urlfrom django.contrib import adminfrom app01 import viewsurlpatterns = [ url(r'^admin/$', admin.site.urls), url(r'^upload/$', views.upload, name='upload'), url(r'^show/$', views.show, name='show'), url(r'^delete/$', views.delete, name='delete'),] views.py from django.shortcuts import render, redirectfrom app01 import models# Create your views here.def upload(request): error = '' if request.method == 'POST': img = request.FILES.get('img') pic_name = img.name if pic_name.split('.')[-1] == 'mp4': error = '暂不支持上传此格式图片!!!' else: models.Images.objects.create(img_name=pic_name, img=img) return redirect('show') return render(request, 'upload.html', locals())def show(request): all_images = models.Images.objects.all() # for i in all_images: # print(i.img) return render(request, 'show.html', locals())def delete(request): pk = request.GET.get('pk') models.Images.objects.filter(id=pk).delete() return redirect('show') show.html <!DOCTYPE html><html lang="en"><head> <meta charset="UTF-8"> <title>展示照片</title></head><body>{% for image in all_images %} <img src="/{{ image.img }}" style="width: 240px;height: 240px;"> <a href="/delete/?pk={{ image.id }}" rel="external nofollow" >删除</a>{% endfor %}<br/><p style="text-align: center;color: #2b542c;font-size: 20px;"> <a href="{% url 'upload' %}" rel="external nofollow" rel="external nofollow" >返回</a></p></body></html> 
6,整体演示一遍
因为时间紧,故以最low方式简要实现,并没有加上漂亮的页面和样式,喜欢美的看客朋友可自行去Bootstrap官网或jq22自行添加!!! 到此这篇关于django将图片保存到mysql数据库并展示在前端页面的实现的文章就介绍到这了,更多相关django 图片保存到mysql内容请搜索51zixue.net以前的文章或继续浏览下面的相关文章希望大家以后多多支持51zixue.net! Python实战之能监控文件变化的神器—看门狗 Python爬虫爬取爱奇艺电影片库首页的实例代码 |