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自学教程:C++ IsLeaf函数代码示例

51自学网 2021-06-01 21:41:41
  C++
这篇教程C++ IsLeaf函数代码示例写得很实用,希望能帮到您。

本文整理汇总了C++中IsLeaf函数的典型用法代码示例。如果您正苦于以下问题:C++ IsLeaf函数的具体用法?C++ IsLeaf怎么用?C++ IsLeaf使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。

在下文中一共展示了IsLeaf函数的30个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的C++代码示例。

示例1: assert

void Tree::ToFileNodeRooted(TextFile &File, unsigned uNodeIndex) const	{	assert(IsRooted());	bool bGroup = !IsLeaf(uNodeIndex) || IsRoot(uNodeIndex);	if (bGroup)		File.PutString("(/n");	if (IsLeaf(uNodeIndex))		File.PutString(GetName(uNodeIndex));	else		{		ToFileNodeRooted(File, GetLeft(uNodeIndex));		File.PutString(",/n");		ToFileNodeRooted(File, GetRight(uNodeIndex));		}	if (bGroup)		File.PutString(")");	if (!IsRoot(uNodeIndex))		{		unsigned uParent = GetParent(uNodeIndex);		if (HasEdgeLength(uNodeIndex, uParent))			File.PutFormat(":%g", GetEdgeLength(uNodeIndex, uParent));		}	File.PutString("/n");	}
开发者ID:Unode,项目名称:ext_apps,代码行数:28,


示例2: NodeName

/*virtual*/ string ComputationNodeBase::FormatOperationPrototype(const string& extraArgs) const{    string prototype;    prototype += msra::strfun::strprintf("%ls = %ls", NodeName().c_str(), OperationName().c_str());    // arguments of operation    if (IsLeaf())        prototype += "()";    else    {        prototype += " (";        for (size_t i = 0; i < GetNumInputs(); i++)        {            const auto& child = m_inputs[i];            if (i > 0)                prototype += ", ";            if (child)                prototype += msra::strfun::strprintf("%ls", child->NodeName().c_str());            else                prototype += "NULL";        }        prototype += extraArgs;        prototype += ")";    }    // type (tensor dimensions) of operation    prototype += " : ";    if (!IsLeaf())    {        //prototype += "(";        for (size_t i = 0; i < GetNumInputs(); i++)        {            const auto& child = m_inputs[i];            if (i > 0)                prototype += ", ";            if (child == nullptr)            {                prototype += "NULL";                continue;            }            prototype += child->ShapeDescription().c_str();        }        prototype += extraArgs;        //prototype += ")";    }    prototype += msra::strfun::strprintf(" -> %s", ShapeDescription().c_str());    return prototype;}
开发者ID:Soukiy,项目名称:CNTK,代码行数:53,


示例3: unitTest

void unitTest() {    TreeType tree = InitTree();    printf("After initlizing tree:/n");    PrintTree(tree);    PositionType question = 0;    PositionType answer = 5;    printf("IsLeaf test 1: %s/n", IsLeaf(tree, question) ? "error" : "pass");    printf("IsLeaf test 2: %s/n", IsLeaf(tree, answer) ? "pass" : "error");    printf("Top test: %s/n", Top(tree) == 0 ? "pass" : "error");    printf("Question test 1: %s/n", strcmp(Question(tree, question), "Is it furry?") == 0 ? "pass" : "error");    printf("Question test 2: %s/n", strcmp(Question(tree, answer), "Is it a lizard?") == 0 ? "pass" : "error");    printf("%s/n", Question(tree, answer));    ReplaceNode(tree, 7, "a kitten", "Is it an adult?");    PrintTree(tree);}
开发者ID:Garyguo2011,项目名称:cs9x,代码行数:15,


示例4: main

/* *  Play the "animal" game, in which the program attempts to guess an animal *  that the user is thinking of by asking yes or no questions. Eventually, *  the program either will guess the user's animal or run out of questions *  to ask. In the latter case, the program will ask the user to provide a *  yes-or-no question that would distinguish between the user's animal and *  the program's best guess. *  The data structure of questions and guesses is essentially a binary tree, *  with each internal node having a "yes" branch and a "no" branch. Leaves *  of the tree represent animals to be guessed by the program. If the program *  fails to guess the user's animal, it replaces one of the leaves of the tree *  by a node containing the new question, whose children are the program's *  best guess and the animal provided by the user. *  The structure of the program is simple. It initializes the question/guess *  data structure, then plays games as long as the user is interested. In each *  game, the program starts at the top of the tree (the root) and progresses *  toward the bottom (the leaves) depending on the user's responses. Once it *  reaches a leaf, it either has won or lost, and handles the situation as *  described above. */int main () {    TreeType tree;    PositionType pos;    char *newQuestion, *newAnswer;    tree = InitTree ();    // unitTest();    printf("%s", "Think of an animal. I will try to guess what it is./n"         "Please answer my questions with yes or no./n");    while (TRUE) {        pos = Top (tree);        while (!IsLeaf (tree, pos)) {            pos = Answer (Question (tree, pos))?            YesNode (tree, pos): NoNode (tree, pos);        }        if (Answer (Guess (tree, pos))) {            printf ("I got it right!/n");        } else {            GetNewInfo (tree, pos, &newAnswer, &newQuestion);            ReplaceNode (tree, pos, newAnswer, newQuestion);        }        if (!Answer ("Want to play again? ")) {            exit (0);        }    }    return 0;}
开发者ID:Garyguo2011,项目名称:cs9x,代码行数:48,


示例5: GetAnyNonLeafNode

unsigned Tree::GetAnyNonLeafNode() const	{	for (unsigned uNodeIndex = 0; uNodeIndex < m_uNodeCount; ++uNodeIndex)		if (!IsLeaf(uNodeIndex))			return uNodeIndex;	return NULL_NEIGHBOR;	}
开发者ID:Unode,项目名称:ext_apps,代码行数:7,


示例6: GetIncrement

float* Node::GetIncrement(){    if(!IsLeaf())        return NULL;    else        return mpCut->GetIncrement();}
开发者ID:lastfallen,项目名称:mlplus,代码行数:7,


示例7: RemoveTile

uint32 RemoveTile(TileGroup* node, Tile* to_delete){    uint32 num_removed = 0;    if(IsLeaf(node))    {        for(uint8 i = 0; i < node->contained_colliders; ++i)        {            if(node->colliders[i] == to_delete)            {                num_removed++;                auto remaining = (MAX_LEAF_SIZE - 1) - node->contained_colliders;                if(remaining > 0)                {                    memmove(&node->colliders[i], &node->colliders[i + 1], sizeof((uint32)node->colliders[i] * remaining));                    node->colliders[i + 1] = 0;                }                else                {                    node->colliders[i] = 0; // This is the last one in the array                }            }        }    }    else    {        TileGroup* child_node = node->child_nodes;        for(uint32 i = 0; i < QUADTREE_CHILDREN; ++i)        {            num_removed += RemoveTile(child_node, to_delete);        }    }    return num_removed;}
开发者ID:ravencgg,项目名称:GLMario,代码行数:35,


示例8: RecalculateBoundingVolume

void BVHNode<BoundingVolumeType>::Insert(Collider* collider, BoundingVolumeType& volume){    // If we are a leaf node, we need to create two new children and put the new body in one of them    if (IsLeaf())    {        m_children[0] = new BVHNode<BoundingVolumeType>(this, m_collider, m_volume);        m_children[1] = new BVHNode<BoundingVolumeType>(this, collider, volume);        m_collider = NULL;          // We are no longer a leaf node, so clear our collider        RecalculateBoundingVolume();    }    // Otherwise, we need to decide which child gets to keep the inserted collider.    // We will give it to the child that would grow the least to incorporate it.    else    {        if (m_children[0]->m_volume.GetGrowth(volume) < m_children[1]->m_volume.GetGrowth(volume))        {            m_children[0]->Insert(collider, volume);        }        else        {            m_children[1]->Insert(collider, volume);        }    }}
开发者ID:gnleece,项目名称:Dogwood,代码行数:26,


示例9: FindFurthestVisitedItem

 MenuItem* MenuItem::FindFurthestVisitedItem() {     if (IsLeaf() || !subitems[markedSubitemIndex]->IsVisited()) {         return this;     } else {         return subitems[markedSubitemIndex]->FindFurthestVisitedItem();     } }
开发者ID:panmar,项目名称:pg3,代码行数:7,


示例10:

inline size_t SpillTree<MetricType, StatisticType, MatType, HyperplaneType,    SplitType>::NumPoints() const{  if (IsLeaf())    return count;  return 0;}
开发者ID:dasayan05,项目名称:mlpack,代码行数:7,


示例11: TraverseBtoF

void HQBSPTreeNode::TraverseBtoF(const HQVector4& eye , const HQPlane * frustum , HQPolygonList &listOut)//traverse front to back.<listOut> will store polygons in back to front order. {	if (this->boundingBox.Cull(frustum , 6) == HQ_CULLED)//nhánh này hoàn toàn n
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